Friday, October 21, 2011

Points and Exact Values of Angles

Hi everyone! I'm Hannah and I'll scribe for yesterday's class. :)


Yesterday, we learned about finding the coordinates of a point of an angle. We've answered a few examples on our booklet and I've listed them below together with its solution. :)





When solving for the point of an angle, we should identify the cos and sin of the given angle. We can get the cos through the SOHCAHTOA. For cos, we should identify the adjacent over hypotenuse. For the sin, we should identify the opposite over hypotenuse.

In our first example, the angle of 30 degrees has a cos of square root of 3 over 2 and 1/2. We should also consider the CAST rule. Since 30 degrees is in quadrant 1, wherein all are positive, the final value of the point is (square root of 3/ 2 , 1/2).


We also learned about finding the exact value of a given angle. Below is an example from our booklet.


The given angle is tangent of 300 degrees. In getting the answer, we will use the SOHCAHTOA again. Since the given is tangent, we will be looking for its opposite over adjacent. The angle 300 degrees is a related angle, with 60 degrees as its reference angle. In the special triangle of 60 degrees, the opposite is square root of 3, and its adjacent is 1. Using the CAST RULE, the 300degrees is in the fourth quadrant, where cos is positive and the rest are negative. Since the given is tangent in quadrant IV, the answer should be negative. So our final answer, the exact value of tan300degrees is -square root of 3.


So yeah, I'm not really good at this so I just hope you learned something. Thanks :)




No comments:

Post a Comment