HEY GUYS, the name's Jean Relleve from Mr.Piatek's prcal 30s class and Im gonna show what we did on Tuesday

Example:

y=x^2+7x-5

ok, im not good with explaining things so please bear with me (srsly tho pls bear with me)

1. we still use the standard form: y=ax^2+bx+c

2.we will move c to the other side (if the # is negative it will be positive when we move it to the other side vice versa)

y=x^2+7x-5

= x^2+7x=5

3. now we'll take b (7) from the equation and divide it by two and then square

x^2+7x=5

(7/2)^2 =49/4

note:you're gonna keep the fraction the way it is

4.Now we're going to add it to both sides of the equation like so

x^2+7x+49/4=5=49/4

now add em all up

x^2+7x+49/4=69/4

and now we're gonna put it into vertex form so all we have to do is switch the # on the left to the other side

(you're going to have to turn 69/4 into a negative when switching sides)

y=(x+7/2)^2-69/4

HOPE THIS HELPS U!

(srsly cuz i dunno if im good at explainin things, ah well we did this stuff in class together anyways)